Compare the bond order, bond enthalpy and bond length in O2+,O2 and O2- using molecular orbital theory.
Answers
Answered by
0
Answer:
In O
2
+
, B.O = (10−5)/2=2.5
In O
2
−
, B.o = (10−7)/2=1.5
Bond dissociation energy is directly proportional to bond order and paramagnetic character depends on unpaired electrons. O
2
+
has high dissociation energy and both are paramagnetic.
Similar questions