Question

Compare the bond order, bond enthalpy and bond length in O2+,O2 and O2- using molecular orbital theory.

Answer 1

Answer:

In O  

2

+

​  

, B.O = (10−5)/2=2.5

In O  

2

−

​  

, B.o = (10−7)/2=1.5

Bond dissociation energy is directly proportional to bond order and paramagnetic character depends on unpaired electrons. O  

2

+

​  

 has high dissociation energy and both are paramagnetic.