Math, asked by rahmannimra96, 6 months ago

compare the change of getting 4with one dice, 8 with two dice and 12 with three dice​

Answers

Answered by kunaltaneja777pddzhn
5

Chances of throwing 4 with one die=

6

1

Chances of throwing with 8 with two die=

total

Expected

Expected=(2,6),(3,5),(4,4),(5,3),(6,2)

Total=36

Probability=

36

5

Chances of throwing 12 with three die=

216

25

Since,Expected=25

and Total=6

n

⇒216

On comparing

6

1

:

36

5

:

216

25

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