Question

Compare the dipole moment for CCl4 , CHCl3 , CH2Cl2 and CHCl3 .​

Answer 1

$\underline{\red{\rm Dipole\ Moment :- }}$

• It is the magnitude of the polarity of the bond .
• It is represented by $\mu$ , and $\mu =\sf q \times d .$
• It is vectors quantity which acts from a less EN atom to more EN atom.

$\bf Comparison :-$

Elcetronegativity order :- H < C < Cl

See attachment . Hence we conclude that ,

$\longrightarrow \sf CCl_4 < CHCl_3< CH_2CL_2 < CH_3Cl \ \ (\mu)$

$\rule{200}2$

Answer 2

Answer:

The order of decreasing dipole moment is CH3Cl> CH2Cl2> CHCl3> CCl4. ... Hence, the dipole moment of CH2Cl2 is lower than the dipole moment of CH3Cl. Similarly, CHCl3 has a lower dipole moment than In CH2Cl2, The net dipole moment of CCl4 is zero because four C−Cl bond dipoles cancel each other.

Explanation: