Question

Compare the dipole moment of cbr4,chbr3,ch2br2 and ch3br

Answer 1

All the structure have tetrahedral geometry, So the vector addition in CBr4 will be equally nullified hence it has 0 dipole moment, CHBr3 has one H which has lesser force hence it has greater dipole moment, similarly CH2BR2 will have even more dipole moment, finally CHBr3 has greatest dipole moment.(the red arrows indicate dipole moment of individual bonds)

NOTE: Br is more electronegative than a sp3 Carbon atom while H is less electronegative than the same, hence direction of the dipole moment they produce individually is different

Answer 2

Answer:

The distance between two electrical charges that are in opposition is measured as a dipole moment.

Explanation:

• Dipole moment of cbr4:

Tetrahedron, which is symmetric in nature, describes the molecular structure of carbon tetrabromide. And because of this symmetry, every dipole cancels out every other one, giving in a total dipole moment of zero.

• Dipole moment of chbr3:

In its molecular structure, CHBr3 lacks a persistent dipole moment. Due to an uneven distribution of positive and negative charges, the CHBr3 molecule lacks a dipole moment.

• Dipole moment of ch2br2:

Due to the significant difference in electronegativity between the H (2.2) and Br (2.96) atoms, which gain partial positive and negative charge correspondingly, CH2Br2 (Dibromomethane) is a polar molecule. A polar molecule, CH2Br2 has a net dipole moment of 1.7 D.

• Dipole moment of ch3br:

The isolated molecule adsorbates' dipole moment, as determined by the best fit, is 2.57 (0.05 for CH3Br).

Thus, the dipole moment is the result of the electric charge and separation between the molecules' positive and negative species.