Question

Compare The Electrostatic Force And Gravitional Force I Electron And Proton In Hydrogen Atom.If Separation Distance B/W Then Is 5.3×10*-11.Can Anybody...???

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Answer 1

Explanation:

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• Electrostatic force between two bodies is given by,

$f(e) = \frac{q1q2}{ 4πe{r}^{2} }$

• Gravitational force between two bodies is given by,

$f(g) = \frac{gm1m2}{ {r}^{2} }$

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therefore,

f(e)/f(g)=

$\frac{f(e)}{f(g)} = \frac{q1q2}{4\piegm1m2}$

here,

• q1=q(e)=1.6×10^-19C
• q2=q(p)=1.6×10^-19C
• m1=m(e)=9.1×10^-31Kg
• m2=m(p)=1.6×10^-27Kg
• g=6.67×10^-11
• 1/4πe=9×10^9

substituting the values we get,

$\frac{f(e)}{f(g)} = \frac{1.6 \times {10}^{ - 19} \times 1.6 \times {10}^{ - 19} \times 9 \times {10}^{9} }{6.67 \times {10}^{ - 11} \times 9.1 \times {10}^{ - 31} \times 1.6 \times {10}^{ - 27} } \\ = \frac{1.6 \times 9 \times {10}^{40} }{6.67 \times 9.1} \\ = 2.4 \times {10}^{39}$

or we can say,

fe=2.4×10^39 times fg

note: e stands for £• (epsilon)

(sorry for the typing mistake of dividing two equations, hope you corrected it, it's not getting edited properly)

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hope it helps.....!!!

Answer 2

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