Question

Compare the energies of electron in the third orbit of He+ ion with the electron in the second orbit of Li 2+ ion.​

Answer 1

Explanation:

The potential energy of an electron in the nth

orbit is given by:

P.E.=− n2

27.2 z

2

eV

As it is lithium-ion ‘z’=3 and as it is 2nd orbit, n=2.

Putting z=3,n=2,

P.E.=−

2

2

27.2×3

2

P.E=−61.2 eV

Answer 2

Answer:

Energies are in the ratio 16:81

Energy in nth orbit = -13.6 (z/n)^2 eV.

{electron Volts} 1eV= 1.602×10^(-19) Coulomb.