Chemistry, asked by Divranjn, 10 months ago

. Compare the energies of two radiations E, with wavelength 800 nm and E2 with wavelength
400 nm.

Answers

Answered by sumith89

0

Answer:

800pm = 8 A° (angstrom)

400pm = 4 A°

Energy of first radiation = 12400 ÷ 8 = 1550 eV

Energy of second radiation = 12400 ÷ 4 = 3100 eV

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