Question

compare the energy of electron in the first three orbit of hydrogen atom​

Answer 1

Answer:

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Explanation:

Energy of an electron is given by,

En=n2−13.6eV, for hydrogen Z=1

For Bohr's second orbit n=2

Therefore, E2=−3.4eV but 1eV=1.6×10−19J

E2=−5.45×10−19J

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