Compare the flashpoint of methane to octane, methanol to octan-1-ol, and methanoic acid and octanoic acid. Explain your rationale using intermolecular forces.
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Ethanoic acid. It forms strong intermolecular bonds with water due to Van der Waals forces.
3) Ethanol. The longer n-alcohol is, the lower the polarity of -OH is.
4) Alkanes, because they are the least polar.
5) Ethanol is more polar, so the intermolecular forces in it are higher then in octanol, and so it is harder to break bonds between moecules and to evaporate
6) Methan < octane; methanol > octan-1-ol; methanoic acid > octanoic acid. The more polar molecule is, the higher it's flashpoint
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