Question

compare the following and foll the blanks with anyone Signs 0= D4-5 anyone of the 2) -51 - (-2) 32-8 – (-11) 4 - 106-10 5-1-0 6)-55_(-58) 71-13 (121) 8) -5 -(-45 (-10000 90 (-16) 90 ) - 10008​

Answer 1

The logic is:

SEDATE : ETADES → The letters in the first word when written from right end to left end, we get the arrangement of letters as shown in the second word.

Similarly,

BRIM : ? → BRIM when written from right to left, we get MIRB

Hence, ‘MIRB’ is the correct answer.

Answer 2

☆ANSWER☆

XC=ωC1=340×50×10−61=58.8 Ω

XC=ωC1=340×50×10−61=58.8 ΩXL=ωL=340×20×10−3=6.8 Ω

XC=ωC1=340×50×10−61=58.8 ΩXL=ωL=340×20×10−3=6.8 ΩZ=R2+(XC−XL)2

XC=ωC1=340×50×10−61=58.8 ΩXL=ωL=340×20×10−3=6.8 ΩZ=R2+(XC−XL)2    =402+(58.8−6.8)2

XC=ωC1=340×50×10−61=58.8 ΩXL=ωL=340×20×10−3=6.8 ΩZ=R2+(XC−XL)2    =402+(58.8−6.8)2    =4304 Ω

XC=ωC1=340×50×10−61=58.8 ΩXL=ωL=340×20×10−3=6.8 ΩZ=R2+(XC−XL)2    =402+(58.8−6.8)2    =4304 ΩPower, P=irms2R=(ZVrms)2R

XC=ωC1=340×50×10−61=58.8 ΩXL=ωL=340×20×10−3=6.8 ΩZ=R2+(XC−XL)2    =402+(58.8−6.8)2    =4304 ΩPower, P=irms2R=(ZVrms)2R                              =(430410/2)2×40

XC=ωC1=340×50×10−61=58.8 ΩXL=ωL=340×20×10−3=6.8 ΩZ=R2+(XC−XL)2    =402+(58.8−6.8)2    =4304 ΩPower, P=irms2R=(ZVrms)2R                              =(430410/2)2×40                              =430450×40≈0.51 W