Question

compare the following surds
√3 and ³√6​

Answer 1

Answer:

$\sqrt[3]{6} > \sqrt{3}$

Step-by-step explanation:

$\sqrt{3} = \sqrt[6]{ {3}^{3} }$

$\sqrt[3]{6} = \sqrt[6]{ {6}^{2} }$

Therefore,

$\sqrt{3} = \sqrt[6]{27}$

$\sqrt[3]{6} = \sqrt[6]{36}$

Now as the roots are the same, we can compare them...

36 > 27

Therefore,

$\sqrt[3]{6} > \sqrt{3}$

Thanks. Hope you liked it. If yes, please mark as brainliest. Stay safe!