compare the formula for capacitors in series and parallel with those for resistors in series or parallel. explain why the pattern is different
Answers
Answer:
I really appreciate the question .
so firstly stating the formulae for both of them .
1/R = 1/r1 + 1/r2 +..........+ 1/rn (resistance in parallel connection )
C = C1 + C2 + C3+...........+Cn (equivalent capacitance in parallel connection )
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R= r1 + r2 +.........+rn (resistance in series )
1/C = 1/c1 + 1/c2 +........+1/cn
Now a very simple sort of explanation I'd like to give so that it's easily understoodv.
The most simple reason is ,
the capacitors when connected in series , the capacitance is less than that of a single capacitor . Which means , when you connect one capacitor in series , it is able to store more charges than five capacitors in series .
And hence the formula is so . You can checkout the derivation of formula in the books . But I've explained why it happens so .
Similarly , when resistances are added up in series , they add up and increase the net resistance unlike capacitors and that is why they are added up algebrically and hence is the formula so . Again , if you want derivation check for it in a book .
Now you yourself can conclude about the parallel connection .
Now a fun fact for you all . If you connect 2 or more bulbs in series , it'll give less brightness than a single bulb in series whereas when you connect 2 or more bulbs in parallel , it'll be more bright than a single bulb in parallel connection .
I hope you're happy with the answer and would always work towards acquiring more knowledge .
Very sorry if I've mistaken somewhere. please correct me if required.
Hope it helps .