Question

Compare the frequencies of note A and C played during a musical concert when the speed of sound is 360m/s and wavelength of A ad C are 1.5m and 1.33m respectively ​

Answer 1

when the speed of sound is 360 metre per second and wavelength of a and c are 1.5 and 1.33 respectively then

Answer 2

Explanation:

As we know that, from the relation, v = v$\lambda $

Frequency of the sound wave (v) = Speed of sound / Wavelength of sound

So, frequency of note A, ${ V }_{ A }$ = 340/1.5= 226.66 Hz

Again, frequency of note C,${ V }_{ c }$ = 340/1.33 = 255.63 Hz

So, frequency of note C is more than frequency of note A