Question

Compare the frequencies of note A and C played during a
musical concert when the speed of sound is 340 m/s and
wavelengths of A and C are 1.5 m and 1.33 m respectively ​

Answer 1

Answer:

Frequency of note c is more than frequency of note A

Explanation:

As we know that, from the relation, v = v$\lambda $

Frequency of the sound wave (v) = Speed of sound / Wavelength of sound

So, frequency of note A, ${ V }_{ A }$ = 340/1.5= 226.66 Hz

Again, frequency of note C,${ V }_{ c }$ = 340/1.33 = 255.63 Hz

So, frequency of note C is more than frequency of note A