Question

Compare the frequency and amplitude of sound waves 1 and 2 given below.​

Answer 1

Answer:

⟹450=

2

1

(20+b)×15

:⟹450×2=(20+b)×15

:⟹900=(20+b)×15

:⟹900=300+15b

:⟹900−300=15b

:⟹600=15b

:⟹b=

15

600

:⟹

b=40m

★

⟹450=

2

1

(20+b)×15

:⟹450×2=(20+b)×15

:⟹900=(20+b)×15

:⟹900=300+15b

:⟹900−300=15b

:⟹600=15b

:⟹b=

15

600

:⟹

b=40m

★

⟹450=

2

1

(20+b)×15

:⟹450×2=(20+b)×15

:⟹900=(20+b)×15

:⟹900=300+15b

:⟹900−300=15b

:⟹600=15b

:⟹b=

15

600

:⟹

b=40m

★

⟹450=

2

1

(20+b)×15

:⟹450×2=(20+b)×15

:⟹900=(20+b)×15

:⟹900=300+15b

:⟹900−300=15b

:⟹600=15b

:⟹b=

15

600

:⟹

b=40m

★

⟹450=

2

1

(20+b)×15

:⟹450×2=(20+b)×15

:⟹900=(20+b)×15

:⟹900=300+15b

:⟹900−300=15b

:⟹600=15b

:⟹b=

15

600

:⟹

b=40m

★