Compare the frequency and amplitude of sound waves 1 and 2 given below.
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Answer:
⟹450=
2
1
(20+b)×15
:⟹450×2=(20+b)×15
:⟹900=(20+b)×15
:⟹900=300+15b
:⟹900−300=15b
:⟹600=15b
:⟹b=
15
600
:⟹
b=40m
★
⟹450=
2
1
(20+b)×15
:⟹450×2=(20+b)×15
:⟹900=(20+b)×15
:⟹900=300+15b
:⟹900−300=15b
:⟹600=15b
:⟹b=
15
600
:⟹
b=40m
★
⟹450=
2
1
(20+b)×15
:⟹450×2=(20+b)×15
:⟹900=(20+b)×15
:⟹900=300+15b
:⟹900−300=15b
:⟹600=15b
:⟹b=
15
600
:⟹
b=40m
★
⟹450=
2
1
(20+b)×15
:⟹450×2=(20+b)×15
:⟹900=(20+b)×15
:⟹900=300+15b
:⟹900−300=15b
:⟹600=15b
:⟹b=
15
600
:⟹
b=40m
★
⟹450=
2
1
(20+b)×15
:⟹450×2=(20+b)×15
:⟹900=(20+b)×15
:⟹900=300+15b
:⟹900−300=15b
:⟹600=15b
:⟹b=
15
600
:⟹
b=40m
★
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