compare the kinetic energy of two identical cricket balls travelling with velocity 3m/s and 4m/s
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Answer:
kinetic energy =1/2mv power2
case 1=
v=3
K.E = 1/2×m×3 power2
=1/2×m×9
=9/2m= 4.5m
case 2=
v=4
K.E= 1/2×m×4power2
=1/2×m×4×4
2×4×m
=8m
now ,
case 1 /case2
= 4.5m/8m
=4.5/8
=45/80
=9/16
thus K.E1:K.E2= 9:16
ANS.
hope this is helpful
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