Question

compare the pairs of ratios 4/9,7/8

Answer 1

Answer:

the pair of ratios in fraction are 4/9 , 7/8

The L.C.M (least common multiple) of 8 and 9 is 72

Making the denominator of each fraction equal to 72, we have

4/9= (4 ×8)/(9 ×8) = 32/72

7/8 = ( 7×9)/(8 ×9) = 63/72

Clearly, 63 > 32

 Now, 63/72 > 32/72

Therefore, 7 : 8 > 4 : 9.

Answer 2

Answer:

We will get $\frac{32}{72}<\frac{63}{72} \text { or } \frac{4}{9}<\frac{7}{8}.$

Step-by-step explanation:

• As per the question we have to evaluate the given data.

        Given data:- $\frac{4}{9} ,\frac{7}{8} .$

       To find:- Compare the pairs of ratios $\frac{4}{9} ,\frac{7}{8} .$

        Solution:-

• Find the least common denominator or LCM of the two denominators:

             LCM of 9 and 8 is 72.

• Next, find the equivalent fraction of both fractional numbers with denominator 72.

• For the 1st fraction, since 9 × 8 = 72

        $\frac{4}{9}=\frac{4 \times 8}{9 \times 8}=\frac{32}{72}$

• Likewise, for the 2nd fraction, since 8 × 9 = 72,

         $\frac{7}{8}=\frac{7 \times 9}{8 \times 9}=\frac{63}{72}$

• Since the denominators are now the same, the fraction with the bigger numerator is the greater fraction.

          $\frac{32}{72}<\frac{63}{72} \text { or } \frac{4}{9}<\frac{7}{8}$