Question

compare the power bused in the 2 ohm resistor in each of the following circuits:

(i); 6v battery in series with 1 ohm and 2 ohm resistor
(!!}; 4V battery in parallel with 12ohm and 2 ohm resistors

WILL MARK AS BRAINLIEST

Answer 1

hey dude....
ur answer is here....!!!!!

a) In a series circuit,
the same current passes through the resistors,
so you can take it to be a constant.
Power is hence given by:
P = (I^2)R

current in the circuit = 6/(2+1) = 2 A

So power dissipated in 2 ohm resistor = (2^2).2 = 8 Watts.

b) Potential difference is constant in a parallel circuit.
Hence power dissipated across the 2 ohm resistor is directly given as:

(V^2)/R = (4^2)/2 = 8 Watts.

thanks....!