compare the power used in 2 ohm resistor in each of the following circuit 1) A 6 v battery in series with 1 ohm and 2 ohm resistors. 2) A 4 v battery in parallel with 12 ohm and 2 ohm resistors
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Answered by
23
1. P =I^2×R
P = 2^2×2
P = 8w
2. P= V^2 / R
P =4^2 / 2
P =8W
hope it helps u
P = 2^2×2
P = 8w
2. P= V^2 / R
P =4^2 / 2
P =8W
hope it helps u
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Answered by
13
p=V^2/R
in 1st case
V^2=36
R=2+1=3Ohm
piwer=36/3=12
in 2nd case
V^2=16
total resistance is 1/12+1/2=14/24
power=16/14/24
=16×24/14=27.5.
power in 2nd case is more
in 1st case
V^2=36
R=2+1=3Ohm
piwer=36/3=12
in 2nd case
V^2=16
total resistance is 1/12+1/2=14/24
power=16/14/24
=16×24/14=27.5.
power in 2nd case is more
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