Question

Compare the power used in 2 ohm resistor on each of the following circuits.

Answer 1

Hello mate ✨

i) In the first case, the two resistors are connected in series.

So the, equivalent resistance, R=R1+R2

R=1+2= 3 ohms

By applying Ohms law,

I=V/R

I=6/3

I=2A

now,

P=I²R

P=2×2×2

P=8 W

ii)Now, the two resistors are connected in parallel, Therefore the potential difference will be the same.

Now, P= V²/R

P= 4×4/2

P=8 W

Answer 2

$\huge\mathfrak{Bonjour!!}$

$\huge\fcolorbox{black}{aqua}{Answer:-}$

⛄ 1) ᴇϙᴜɪᴠᴀʟᴇɴᴛ ʀᴇsɪsᴛᴀɴᴄᴇ ᴏғ 1 Ω ᴀɴᴅ 2 Ω ɪɴ sᴇʀɪᴇs, ʀ = 1Ω + 2Ω = 3Ω

ᴘᴏᴛᴇɴᴛɪᴀʟ ᴅɪғғᴇʀᴇɴᴄᴇ, ᴠ = 6 ᴠ

ᴄᴜʀʀᴇɴᴛ, ɪ = ᴠ/ʀ = 6/3 = 2 ᴀ

ᴄᴜʀʀᴇɴᴛ ɪɴ sᴇʀɪᴇs ᴄɪʀᴄᴜɪᴛ ɪs sᴀᴍᴇ.

ᴛʜᴇʀᴇғᴏʀᴇ,

ᴄᴜʀʀᴇɴᴛ ɪɴ 2 Ω ʀᴇsɪsᴛᴏʀ = 2 ᴀ.

ᴘᴏᴡᴇʀ ɪɴ 2 Ω ʀᴇsɪsᴛᴏʀ, ᴘ = 1²ʀ = 2² × 2 = 8 ᴡ

⛄ 2) ᴘᴏᴛᴇɴᴛɪᴀʟ ᴅɪғғᴇʀᴇɴᴄᴇ ᴀᴄʀᴏss 2 Ω ʀᴇsɪsᴛᴏʀ = 4 ᴠ

ᴘᴏᴡᴇʀ, ᴘ' = ᴠ²/ʀ = 4²/2 = 8 ᴡ.

ᴛʜᴇʀᴇғᴏʀᴇ,

ᴘ : ᴘ' = 8 ᴡ : 8 ᴡ = 1 : 1 ᴀɴs.

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