Question

Compare the power used in the 2 2 resistor in each of the following circuits:
(1) a 6V battery in series with 1 and 2 12 resistors, and (u) a 4 V battery in parallel
with 122 and 2 2 resistors.​

Answer 1

Answer:

Given :-

Potential difference = 6 V

Solution :-

Equivalent resistance = 1 + 2 = 3 Ω

According to the Ohm’s law

V = IR

I = V/R

I = 6/3

I = 2 A

Current through the circuit = 2 A

we know that Power = I²R

P = 2 × 2 × 2

P = 8 W

Hence, the power used by 2 Ω resistor is 8 W.

Answer :- (ii)

Given :-

Potential difference, V = 4 V

Voltage across each component of a parallel circuit remains the same. Then,

Solution :-

P = V²/R

P = 4²/2

P = 8 W

Hence, the power used by 2 Ω resistor is 8 W.

Explanation:

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