Question

Compare the power used in the 2 Ohm resistor in each of the following circuits: (i) a 6 V battery in series with 1 Ohm and 2 Ohm resistors, and (ii) a 4 V battery in parallel with 1 Ohm and 2 Ohm resistors.
please solve quick please.​

Answer 1

Answer:

To find : Compare the power used in 2 ohm resistor in each of the following Circuits,

(1) a 6 V battery in series with 1 ohm and 2 ohm resistors.

(2) a 4 V battery in parallel with 12 ohm and 2 ohm resistor

Solution :

1) The potential difference is V=6V

1 Ω and 2 Ω resistors are connected in series.

So, Equivalent resistance of the circuit is R=1+2=3 Ω.

According to Ohm’s law

I=\frac{V}{R}I=

R

V

I=\frac{6}{3}I=

3

6

The current through the circuit (I)=2 Ampere.

Now, The power used in the 2 Ω resistor is given by,

P=I^2RP=I

2

R

P=2^2\times 2P=2

2

×2

P=8\ WP=8 W

2) The potential difference is V=4V

12 Ω and 2 Ω resistors are connected in parallel.

The voltage across each component of a parallel circuit remains the same.

The power used in the 2 Ω resistor is given by,

P=\frac{V^2}{R}P=

R

V

2

P=\frac{4^2}{2}P=

2

4

2

P=8\ WP=8 W