Compare the power used in the 2 resistor in each of the following circuits:
(1) a 6V battery in series with 1ohm and 2ohm resistors, and (11) a 4 V battery in parallel
with 12ohm
and 2ohm resistors.
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Answer:
formula to find power consumed is P = V^2 /R
Step-by-step explanation:
(i) Given,
potential difference (V) = 6V
resistance1 (R1) = 1 ohm
resistance2 (R2) = 2ohm.
A/Q,
total resistance = R2 + R1
total resistance = 2 + 1
total resistance = 3ohm.
therefore, power consumed is 6V ^2 / 3ohm = 36/3 = 12watt.
(ii) given,
V = 4V
R1 = 12ohm
R2 = 2ohm.
A/Q,
1/total resistance = 1/R1 + 1/R2
= 1/12 +1/ 2
= 1+6/12
= 7/12
P = V^2/R
= 4^2/ 7/ 12
= 16×12/7
= 192/7
= 27.4ohm.
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