Question

Compare the power used in the 2 Ω resistor in each of the following circuits: (i) a 6 V battery in series with 1 Ω and 2 Ω resistors, and (ii) a 4 V battery in parallel with 12 Ω and 2 Ω resistors.

Answer 1

R1+R2=1+2=3 R=V/I

I=V*R. 4*3=12

Answer 2

Answer:

Ans. (c) 20J

Explanation: Total resistance of combination = 2ohm+4ohm= 6ohm

Current through the circuit can be calculated as follows:

$i = \frac{v}{r}$

which is =6v/6ohm=1A

Heat dissipation by 4ohm can be calculated as follows:

H=I²Rt = (1.4)² x 4ohm x 5s = 20J

hopeit helps you