. Compare the power used in the 2 Ω resistor in each of the following circuits: (i) a 6 V battery in series with 1 Ω and 2 Ω resistors, and (ii) a 4 V battery in parallel with 12 Ω and 2 Ω resistors
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Answered by
10
in first case I=2A
so power =I^2R=4.2=8
in second case=v^2/R=16/2=8
so P1:P2=1:1
Answered by
16
Answer:
Explanation:
(i) Total resistance (R) = 2 + 1 = 3 Ω.
Current (I) = 6 V/3 Ω = 2 A
Power used in 2 Ω resistor = I2R = 8 W
(ii) in Parallel voltage is same across all the resistance. So
Power used in 2 Ω resistor = = = 8
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