Question

. Compare the power used in the 2 Ω resistor in each of the following circuits: (i) a 6 V battery in series with 1 Ω and 2 Ω resistors, and (ii) a 4 V battery in parallel with 12 Ω and 2 Ω resistors​

Answer 1

in first case I=2A

so power =I^2R=4.2=8

in second case=v^2/R=16/2=8

so P1:P2=1:1

Answer 2

Answer:

Explanation:

(i) Total resistance (R) = 2 + 1  = 3 Ω.

Current (I) = 6 V/3 Ω = 2 A

Power used in 2 Ω resistor = I2R = 8 W

(ii) in Parallel voltage is same across all the resistance. So

Power used in 2 Ω resistor =  = = 8