Question

Compare the quadratic equation and find the value of discriminants and write the nature of the root .
${x}^{2} + \sqrt[9]{3}x + 24 = \: 0 \\ \\ ax {}^{2} + bx + c$
compare these numbers..

Answer should be respective and correct otherwise I will report!!!!!!!​

Answer 1

Step-by-step explanation:

a=1 b= 3^(1/9) c=24

b^2 - 4 (a) (c)

=(3^(1/9))^2 - 4(1)(24)

=9^(1/9)-96

The value of first term will definitely be less than 96. So, the discrimant is negative. Thus the equation has negative roots.