Compare the quantities ab +ac+k and ab +k-ac, if c is negative rational number
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Answer:
(ab + ac + k) > (ab + k - ac)
Step-by-step explanation:
The reason being that :
We know that every negative number is clearly smaller that every positive number.
Thus, on similar logic, we have two equations -
(i) ab + ac + k
(ii) ab + k - ac
If we compare equations (i) and (ii), we get that, in both of them ab + k is common. Thus the value of both equations till ab + k is equal. But we can notice that in equation (i) there is + ac and in equation (ii) there is (-ac) . Hence in equation (i) ac is added but in equation (ii), ac is subtracted. Clearly equation (i) is greater than equation (ii).
eq. (i) > eq. (ii).
Hence,
(ab + ac + k) > (ab + k - ac)
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