Question

Compare the radial length of Serond orbit of h atom with the same of fourth orbit of He+ ion.​

Answer 1

Answer:

It is given that the quantisation rule followed in aliens' planet is as follows:

mvr=

4π

nh

The change in quantisation rule will not affect the energy difference.

The energy difference (in eV) is given by the expression =E

n

−E

n

′

=−13.6×[

n

2

1

−

n

′2

1

]

We need to find the energy difference between fourth and second orbits.

E

4

−E

2

=−13.6[

4

2

1

−

2

2

1

]

E

4

−E

2

=−13.6×[0.0625−0.25]=−13.6×(−0.1875)=2.55 eV

Hence, the energy difference between fourth and second orbits for H atom is 2.55 eV

Explanation:

hope it helps