Question

Compare the radii of two nuclei with mass numbers 8 in 64 also compare the densities

Answer 1

ANSWER:

$\frac{d_{1}}{d_{2}}=\frac{1}{1}=1 : 1$

EXPLANATION:

The mass number of the radii of the two nuclei is given as 8 and 64 meaning

The radius of the nuclei is the cube root of the mass number of the element given

$A_{1}=8, A_{2}=64$

$\frac{R_{1}}{R_{2}}=\left(\frac{A_{1}}{A_{2}}\right)^{1 / 3}$

$\frac{R_{1}}{R_{2}}=\left(\frac{8}{64}\right)^{1 / 3}$

$\frac{R_{1}}{R_{2}}=\frac{2}{4}=\frac{1}{2}$

Therefore, the radius of the two nuclei which depends on their mass number is given as 1:2 and on the other hand. The density of all the nuclei is considered same, meaning the ratio between the density of the two nuclei is  

$\frac{d_{1}}{d_{2}}=\frac{1}{1}=1 : 1$