Question

Compare the ranges of two projectiles projected with the same velocity at angles θ° to horizontal and θ°to the vertical

Answer 1

Answer:

h=(u^2)sin(2theta) / g , where theta is the angle with which the projectile was projected with the horizontal.

This formula states that the maximum height reached by the projectile is directly proportional to the sine of double angle.

So, the ratio will be sin(60)/sin(120)= 1

Also, as these angles are complementary, i.e. 60+30 = 90 degrees

The maximum height reached by these projectiles will be same

Answer 2

✿━━━━@Mg━━━━✿

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✿━━━━@Mg━━━━✿

h=(u^2)sin(2theta) / g , where theta is the angle with which the projectile was projected with the horizontal.

So, the ratio will be sin(60)/sin(120)= 1

Also, as these angles are complementary, i.e. 60+30 = 90 degrees

The maximum height reached by these projectiles will be same