Question

Compare the rational number
6by 18to 36by18
Explain

Answer 1

$\frac{6}{18 } \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \frac{36}{18} \\ \\ \\ \frac{36}{18} \ \: \: \: is \ \: \: greater$

As the denominators are same which hasn't to be looked up (but if there was unlike denominator we would gave to make them like first). Now, by viewing the numerator i.e 6 & 36, it is seen that 36 is greater one.

Hence, The fraction 36/18 is greater.

$Also, \: we \: can \: see \: this \: again \: by \: converting \: the \: fraction \\ into \: decimal \\ \\ \\ i.e \: \: \frac{6}{18} = 0.33 \: \: \: \: \: \: \& \: \: \: \: \: \frac{36}{18} = 2 \\ \\ hence \\ \: \: \: \: \: \: \: \: \: \: \: \: it \: is \: again \: proved \: that \: 0.33 < 2 \: \: \: \: or \: \: \: \frac{6}{18} < \frac{36}{18}$