Math, asked by nishu5541, 7 months ago

compare the ratios √13 /√8 , √8 /√5

Answers

Answered by pulakmath007
24

\displaystyle\huge\red{\underline{\underline{Solution}}}

TO COMPARE

 \displaystyle \sf{ \frac{ \sqrt{13} }{ \sqrt{8} }  \:  \:  \:  \:  \: and \:  \:  \:  \:  \frac{ \sqrt{8} }{ \sqrt{5} }   \: }

CALCULATION

 \sf{The \:  denominators \:  of \:  the \:  ratios \:  are   \:  \:  \sqrt{8} \: \: and \:  \:  \sqrt{5}  }

Now LCM of 8 & 5 = 40

We rewrite the given ratios as follows

 \displaystyle \sf{ \frac{ \sqrt{13} }{ \sqrt{8} }   =  \frac{ \sqrt{13 \times 5} }{ \sqrt{8 \times 5} }  =  \frac{ \sqrt{65} }{ \sqrt{40} }  \: }

 \displaystyle \sf{ \frac{ \sqrt{8} }{ \sqrt{5} }   =  \frac{ \sqrt{8 \times 8} }{ \sqrt{8 \times 5} }  =  \frac{ \sqrt{64} }{ \sqrt{40} }  \: }

 \sf{Since \:  \:65 > 64 }

Hence

 \displaystyle \sf{ \frac{ \sqrt{13} }{ \sqrt{8} }  \:  \: >  \:  \:  \frac{ \sqrt{8} }{ \sqrt{5} }   \: }

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