Compare the relative stability of the following species and indicate their magnetic properties: O2, O2, O2 – (Superoxide),O2 2- (peroxide)
Answers
Answered by
0
Answer:
ANSWER
(1) The electronic configuration of O
2
molecule is
KK(σ2s)
2
(σ
∗
2s)
2
(σ2p
z
)
2
(π2p
x
)
2
(π2p
y
)
2
(π
∗
2p
x
)
1
(π
∗
2p
y
)
1
Its bond order is
2
8−4
=2.
It contains 2 unpaired electrons and is paramagentic.
(2) The electronic configuration of O
2
+
ion is
KK(σ2s)
2
(σ
∗
2s)
2
(σ2p
z
)
2
(π2p
x
)
2
(π2p
y
)
2
(π
∗
2p
x
)
1
Its bond order is
2
8−3
=2.5.
It contains 1 unpaired electron and is paramagnetic.
(3) The electronic configuration of O
2
−
ion is
KK(σ2s)
2
(σ
∗
2s)
2
(σ2p
z
)
2
(π2p
x
)
2
(π2p
y
)
2
(π
∗
2p
Similar questions