Question

Compare the resistances of two bulbs of 50 watt and 200 watt if they
are at the same voltage.​

Answer 1

⭐《ANSWER》

$\huge\mathfrak{\underline {\underline\pink {ANSWER}}}$

↪Actually welcome to the concept of the CURRENT ELECTRICITY

↪basically here we are going to use the Concept of the Power in the Resistors

↪Since we know that,

↪Power = I^2 R or , Power = V^2/R

↪Since here , we have the same voltage here we get as ,

↪For Bulb A let the , Resistance be R1 and for the Bulb B let the Resistance be R2

↪so we get as ,

↪50 = V^2 / R1 _____(1)

↪and 200 = V^2 /R2 _____(2)

↪since voltage is same , we can equate equation (1) & (2)

↪so here ,

↪R1 ( 50) = R2 ( 200)

↪so ==》 R1/R2 = 200/50

〽R1/R2 = 4

↪so we get as the ratio ,

⭐R1:R2 = 4:1

Answer 2

$\Large{\mathfrak{\underline{\underline{Answer :-}}}}$

$\boxed{\underline{\sf{4 : 1}}}$

$\\ \\ \rule{200}{2}$

$\Large{\mathfrak{\underline{\underline{Solution :-}}}}$

Given in Attachment.

$\\ \rule{200}{2}$