Compare the size of Al3+, Mg2+ and Ca2+.
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Answer:
Explanation:
Al3+ - 10 electrons, 13protons
Mg2+ - 10electrons , 12protons
Here both have same no. of electrons but different no. of protons(Z).
As Al3+ has more protons so its electrons would be attracted more towards nucleus resulting in a size smaller than mg2+
Therefore Al3+ will havea lower ionic radius(its not called atomic radius for ions) than mg2+
Hope it helps
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