compare the size of the largest planet Jupiter to that of the smallest planet Mercury in the solar system by expressing their radii in the standard form.Given that the radius of Jupiter 69911 km and radius of mercury 2439.7km
Answers
Given : radius of Jupiter 69911 km and radius of mercury 2439.7km
To Find : compare the size of the largest planet Jupiter to that of the smallest planet Mercury in the solar system by expressing their radii in the standard form
Solution:
Very large and very small numbers can be expressed in standard form.•
Standard form is also called scientific notation form
A number is written in scientific notation if it has the form c × 10ⁿ where
c ≥1, c < 10, and n is an integer.
radius of Jupiter 69911 km
= 6.9911 * 10⁴ km
radius of mercury 2439.7km
= 2.4397 * 10³
6.9911 * 10⁴ > 2.4397 * 10³
Learn More:
Standard form of 0.00003904 and 1273000 - Brainly.in
brainly.in/question/17597415
Sara and Sam are each working on a science project in which they ...
brainly.in/question/12489921
A worker bee has a mass of ,1cdot{ 10^{-4}}1⋅10
brainly.in/question/9285002
Step-by-step explanation:
your answer is in the attachment hope it will helps you