Compare the speeds of the following cars:
(i) The first car crosses two electric posts which are 40m apart in 2 seconds.
(II) The second car covers a distance of 108 km in 2 hrs.
Answers
Answered by
7
Answer:
The first car is faster than the second
Step-by-step explanation:
Speed of 1st Car = Distance ÷ Time
= 40÷2
= 20 m/s
Speed of 2nd Car = Distance ÷ Time
= 108 ÷ 2
= 54 km/hr
To convert Km/hr into m/s , we need to multiply it with 5/18
54× 5/18
15m/s = Speed of 2nd car
Thus , 1st car is faster...
Similar questions