Question

compare the time period of a simple pendulum at places where g is 9.8 metre per second square and 4.36 metre per second square respectively​

Answer 1

Answer:

Time period Inversely proportional to √g

T1/T2 = √g2/g1

T1/T2 = √4.36/9.8

T1/T2 = 1/1.5

T2 is 1.5 times of T1

Thanks for Reading

Answer 2

Answer:

A simple pendulum is made of a long string and a tiny metal sphere, steel or preferably lead (higher density).  The period of oscillation of a simple pendulum may be found by the formula

in this question in first case take g=9.8 m s power-2

and in second case take g=4.36 m a power -2

here length of string l will same in both case☝️

Hope this helps you

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