Compare the time period of two pendulum of length 1m and 9m...
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Answer:
T =2π√l/g T1= time period of pendulum of length 1m and T2 =time period of pendulum of length 9m
Step-by-step explanation:
T1= 2π√1/g, T2=2π√9/g
by dividing T1/T2
T1= 2π√1/g
T2 2π√9/g
T1=1
T2=3
3T1=T2
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hi dear ARMY how are u dear
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