Question

Compare the time period of two pendulums.Of length 1m and 9

Answer 1

$t =2\pi \sqrt{ \frac{l}{g} } \\ t1 = 2\pi\sqrt{ \frac{1}{10} } = 1.98$

$t2 = 2\pi \sqrt{ \frac{9}{10} } = 5.65$

$\frac{t1}{t2} = \frac{1.98}{5.65} = 0.35$

I hope this helps ( ╹▽╹ )