Compare the time period of two pendulums of length 2m and 9m at a place.
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Answer:
T' = 3T/✓2
Explanation:
T = 2π ✓(l/g)
for this question
T is directly proportional to ✓l
therefore, T/T' = ✓(l/l')
T = T' ✓(2/9)
Or. T' = 3T/✓2
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