Question

compare the time period of two pendulums of length 9 metre and 1m​

Answer 1

Answer:

Time period of pendulam is

T= 2π √(L÷g)

where L is the length of the pendulam.

g is the acceleration due to gravity.

so time period is proportional to the square root of the length.

if the two pendulam's time period is T(1) and T(2) and length L(1) and L(2) respectively then,

T(1) : T(2) = √L(1) : √L(2)

=√1 : √9

= 1 : 3

Answer 2

Answer:

10 m of a pendulam

Explanation:

9+1 =10m