Question

Compare the time period of two simple pendulum of length 4.9m and 8.1m.

tell me the answer of this..​

Answer 1

Answer:

Correct option is

C

2.12

l=1.12m; g=9.8ms

−2

; T=?

T=2π

g

l

=

7

2×22

9.8

1.12

=

7

44

0.114

=

7

44

×0.338=2.12s

Answer 2

refer to attachment..its correct one

first assume two cases then apply formula of time period for simple pendulum in both of them

case one has length 4.9 metre and case 2 has length 8.1 m since 49 and 81 are square of 7 and 9 the calculation is easy to solve , get both the answers and compare them ...