Question

compare the time period of two simple pendulum of length one metre and 16 metre at a place​

Answer 1

Answer:

1 : 4

Explanation:

Time period is directly proportional to square root of length if gravity is constant

(let time period in 1st case =x ; 2nd case = y)

$\frac{x}{y} = \sqrt{ \frac{l}{16 \: l} } \\ \frac{x}{y} = \sqrt{ \frac{1}{16} } \\ \frac{x}{y} = \frac{1}{4}$

Answer 2

ans:1:4 ..l2 is 1 and l1 is 16

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