Question

Compare the time period of two simple pendulums of length 2 m and 8 m at a place. Please answer with explanation ​

Answer 1

Answer:

$FORMULA \: \: for \: time \: period$

$t = 2\pi \sqrt{ \frac{l}{g} }$

Time period lf pendulum of length 2m

$t1 = 2\pi \sqrt{ \frac{2}{g} }$

Time period lf pendulum of length 8m

$t1 = 2\pi \sqrt{ \frac{8}{g} } \rightrightarrows \: 4\pi \sqrt{ \frac{2}{g} }$

Comparison

Time period of first pendulum (length 2m) is half of time period of secomd pendulum (length 8m)

Additional information

• PENDULUM 1 (L=2M) WILL TAKE LESS TIME THAN PENDULUM 2 IN COMPLETING 1 OSSCILATION

• PENDULUM OF LENGTH 1M TAKES 2 SECODNDS FOR one oscillation

• Time period is independent of mass of pendulum