Question

Compare the time periods of a simple pendulum at a place where g = 9.8 m/s2 and 2.45m/s2 respectively​

Answer 1

Answer:

$\frac{1}{2}$

Explanation:

$\frac{t1}{t2} = \sqrt{\frac{g2}{g1} } \\\sqrt{\frac{2.45}{9.8} } \\\sqrt{\frac{12.25}{49} } \\\frac{3.5}{7} \\\frac{0.5}{1}$thus,

$\frac{1}{2}$