Compare the time periods of two simple
pendulums of length 1 m and 16 m at a place
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Answer:
lets say they are again in phase when shorter pendulum has made n
1
oscillations and bigger pendulum n
2
oscillations. so total time elapsed =T
1
×n
1
=T
2
×n
2
⇒
n
2
n
1
=
T
1
T
2
=
l
1
l
2
=
1
16
=
1
4
they will again be in phase for the first time when the shorter pendulum has made 4 oscillations and the longer pendulum has made 1 oscillation.
Explanation:
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