Question

Compare the time periods of two simple pendulums of length 4m and 16m at a place

Answer 1

Answer: They are in the ratio 1:2

Explanation:

Hope this helps you...

Answer 2

We know Time period = 2$\pi$$\sqrt{\frac{L}{g} }$

For L=4m : T₁=2$\pi$$\sqrt{\frac{4}{g} }$

For L=16m : T₂=2$\pi$$\sqrt{\frac{16}{g} }$

Ratio of T₁ / T₂ :

= $\sqrt{\frac{4}{16} }$

= $\frac{1}{2}$

⇒ T₂=2T₁