Question

Compare the time periods of two simple pendulums of length 4 m and 25m at a place... ​

Answer 1

T

T 1

T 1

T 1 =2π

T 1 =2π g

T 1 =2π g1

T 1 =2π g1

T 1 =2π g1

T 1 =2π g1

T 1 =2π g1

T 1 =2π g1 T

T 1 =2π g1 T 2

T 1 =2π g1 T 2

T 1 =2π g1 T 2 =2π

T 1 =2π g1 T 2 =2π g

T 1 =2π g1 T 2 =2π g9

T 1 =2π g1 T 2 =2π g9

T 1 =2π g1 T 2 =2π g9

T 1 =2π g1 T 2 =2π g9

T 1 =2π g1 T 2 =2π g9 =3×2π

T 1 =2π g1 T 2 =2π g9 =3×2π g

T 1 =2π g1 T 2 =2π g9 =3×2π g1

T 1 =2π g1 T 2 =2π g9 =3×2π g1

T 1 =2π g1 T 2 =2π g9 =3×2π g1

T 1 =2π g1 T 2 =2π g9 =3×2π g1

T 1 =2π g1 T 2 =2π g9 =3×2π g1 =3T

T 1 =2π g1 T 2 =2π g9 =3×2π g1 =3T 1

T 1 =2π g1 T 2 =2π g9 =3×2π g1 =3T 1

T 1 =2π g1 T 2 =2π g9 =3×2π g1 =3T 1

T 1 =2π g1 T 2 =2π g9 =3×2π g1 =3T 1 therefore time period of second pendulum is thrice of first pendulum.

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