Question

. Compare the time periods of two simple pendulums of length in the ratio 36m and 4m.​

Answer 1

Answer:

     T₁ : T₂ = 3 : 1

Explanation:

Time period (T) = 2π √L/g

T₁ = 2π × √36 / g

T₂ = 2π × √4 / g

T₁ : T₂

= 2π × √36 / g ÷ 2π × √4 / g

= 2π × √36 / g  ×  g / 2π × √4

2π and g will be cancelled on both sides

= √36 / √4

= 6 / 2

= 3 / 1

T₁ : T₂ = 3 : 1

      Please Mark My Answer As Brainliest

                      ⊕Thank You ⊕

Answer 2

Explanation:

see the attachment for your answer